chore: reformat properly the library file

Missed reformatting.

Signed-off-by: Raito Bezarius <masterancpp@gmail.com>

lib/default.nix

@@ -10,8 +10,8 @@ rec {
 
   inRange = i: range: i >= range.start && i < range.end;
 
-  # Build a selector function that will filters point-by-point any index in xs. 
-  # e.g. if you want to select specific indexes you can just use that. 
+  # Build a selector function that will filters point-by-point any index in xs.
+  # e.g. if you want to select specific indexes you can just use that.
   # If you want to select contiguous interval of indexes, you are better served by
   # `mkIntervalFilter`.
   mkPointwiseFilter = xs: index: any (allowedIndex: index == allowedIndex) xs;
@@ -21,26 +21,26 @@ rec {
   # to `inRange`.
   mkIntervalFilter = intervals: index: any (allowedRange: inRange index allowedRange) intervals;
 
-  # Build an attribute set map from values to indexes. 
+  # Build an attribute set map from values to indexes.
   # e.g. reversedEnumerate [ "a" "b" ] == { "a" = 0; "b" = 1; }.
-  reversedEnumerate = list: listToAttrs 
-    (zipListsWith 
+  reversedEnumerate = list: listToAttrs
+    (zipListsWith
       (index: value: nameValuePair value index)
       (range 0 (length list - 1))
     list);
 
   # Collect a list of attribute sets into an attribute set.
   # Merge order depends on attrValues iteration order and foldl.
-  chainAttrs = attrs: foldl (a: b: a // b) (builtins.attrValues attrs);
+  chainAttrs = attrs: foldl (a: b: a // b) { } (builtins.attrValues attrs);
 
   # Given an attribute set of an attribute set of items, does it describe a valid partition of some global set?
   # This does not check for completeness.
   # idFunction :: Attrs K V → List Identifier
-  isValidPartition = attrs: 
+  isValidPartition = attrs:
   let
     values = builtins.attrValues attrs;
-  in 
-  # TODO(performance?): this is the simple dumb idea. 
+  in
+  # TODO(performance?): this is the simple dumb idea.
   # A better idea would use n(n - 1)/2 iterations over values to exploit symmetry of item equality.
   # To do so, a strategy could be to consider all shifted toplevel identifiers lists and zip them.
   # There's sum_k(n - k) such lists, and therefore: n(n - 1)/2 lists.
@@ -48,16 +48,16 @@ rec {
   # So, if we have N subsets in the partition and each subset has at most K items, we end up doing something like (K log K) * N(N - 1)/2
   # In practice, K should be the biggest and N is quite small.
   lib.all (subset:
-    lib.all (anotherSubset: 
+    lib.all (anotherSubset:
       subset != anotherSubset -> lib.intersectAttrs subset anotherSubset == {}
     ) values
   ) values;
 
-  # Renumber an attribute set of items. 
+  # Renumber an attribute set of items.
   # For each item in the attribute set, we replace its value by a call to the renumbering function
-  # where we pass renumberedIndex and value. 
-  # It's a form of imap for attribute sets. 
-  renumber = indexFn: renumberingFn: attrs: 
+  # where we pass renumberedIndex and value.
+  # It's a form of imap for attribute sets.
+  renumber = indexFn: renumberingFn: attrs:
   let
     indexes = reversedEnumerate (map (n: toString (indexFn n)) (builtins.attrValues attrs));
   in